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84x+105=12x^2-12x
We move all terms to the left:
84x+105-(12x^2-12x)=0
We get rid of parentheses
-12x^2+84x+12x+105=0
We add all the numbers together, and all the variables
-12x^2+96x+105=0
a = -12; b = 96; c = +105;
Δ = b2-4ac
Δ = 962-4·(-12)·105
Δ = 14256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14256}=\sqrt{1296*11}=\sqrt{1296}*\sqrt{11}=36\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-36\sqrt{11}}{2*-12}=\frac{-96-36\sqrt{11}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+36\sqrt{11}}{2*-12}=\frac{-96+36\sqrt{11}}{-24} $
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